(x^2)+x=1190

Solution for (x^2)+x=1190 equation:

(x^2)+x=1190

We move all terms to the left:

(x^2)+x-(1190)=0

a = 1; b = 1; c = -1190;
Δ = b2-4ac
Δ = 12-4·1·(-1190)
Δ = 4761
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{4761}=69$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(1)-69}{2*1}=\frac{-70}{2}
=-35
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(1)+69}{2*1}=\frac{68}{2}
=34
$